2+40/x+0.1*x=2+0.2*x

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Solution for 2+40/x+0.1*x=2+0.2*x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

0.1*x+40/x+2 = 0.2*x+2 // - 0.2*x+2

0.1*x-(0.2*x)+40/x-2+2 = 0

0.1*x-0.2*x+40/x-2+2 = 0

40*x^-1-0.1*x = 0

x^-1*(40-0.1*x^2) = 0

-0.1*x^2 = -40 // : -0.1

x^2 = 400

x^2 = 400 // ^ 1/2

abs(x) = 20

x = 20 or x = -20

1/x = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x naleu017Cy do O

x in { 20, -20 }

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