2+4b=3(b+3)+1

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Solution for 2+4b=3(b+3)+1 equation: 



2+4b=3(b+3)+1

We move all terms to the left:

2+4b-(3(b+3)+1)=0



We calculate terms in parentheses: -(3(b+3)+1), so:

3(b+3)+1

We multiply parentheses

3b+9+1

We add all the numbers together, and all the variables

3b+10

Back to the equation:

-(3b+10)



We get rid of parentheses

4b-3b-10+2=0

We add all the numbers together, and all the variables

b-8=0

We move all terms containing b to the left, all other terms to the right

b=8

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