2+4k=6k-2(1k-1)

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Solution for 2+4k=6k-2(1k-1) equation: 



2+4k=6k-2(1k-1)

We move all terms to the left:

2+4k-(6k-2(1k-1))=0

We add all the numbers together, and all the variables

4k-(6k-2(k-1))+2=0



We calculate terms in parentheses: -(6k-2(k-1)), so:

6k-2(k-1)

We multiply parentheses

6k-2k+2

We add all the numbers together, and all the variables

4k+2

Back to the equation:

-(4k+2)



We get rid of parentheses

4k-4k-2+2=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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