2+4p=10(3/5p-2)

Solution for 2+4p=10(3/5p-2) equation:

2+4p=10(3/5p-2)

We move all terms to the left:

2+4p-(10(3/5p-2))=0


Domain of the equation: 5p-2))!=0

p∈R


We multiply all the terms by the denominator


4p*5p+2*5p-2))-(10(3-2))=0

We add all the numbers together, and all the variables

4p*5p+2*5p-2))-(101)=0

We add all the numbers together, and all the variables

4p*5p+2*5p=0

Wy multiply elements

20p^2+10p=0

a = 20; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·20·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*20}=\frac{-20}{40}
=-1/2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*20}=\frac{0}{40}
=0
$