2+5(3u-2)=-2(4-2)+7u

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Solution for 2+5(3u-2)=-2(4-2)+7u equation: 



2+5(3u-2)=-2(4-2)+7u

We move all terms to the left:

2+5(3u-2)-(-2(4-2)+7u)=0

We add all the numbers together, and all the variables

5(3u-2)-(-22+7u)+2=0

We multiply parentheses

15u-(-22+7u)-10+2=0

We get rid of parentheses

15u-7u+22-10+2=0

We add all the numbers together, and all the variables

8u+14=0

We move all terms containing u to the left, all other terms to the right

8u=-14

u=-14/8

u=-1+3/4

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