2+5(f+3)=2+5(f+3)=2

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Solution for 2+5(f+3)=2+5(f+3)=2 equation: 



2+5(f+3)=2+5(f+3)=2

We move all terms to the left:

2+5(f+3)-(2+5(f+3))=0

We multiply parentheses

5f-(2+5(f+3))+15+2=0



We calculate terms in parentheses: -(2+5(f+3)), so:

2+5(f+3)

determiningTheFunctionDomain
5(f+3)+2

We multiply parentheses

5f+15+2

We add all the numbers together, and all the variables

5f+17

Back to the equation:

-(5f+17)



We add all the numbers together, and all the variables

5f-(5f+17)+17=0

We get rid of parentheses

5f-5f-17+17=0

We add all the numbers together, and all the variables

=0

f=0/1

f=0

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