2+5(i-3)=7i-15-4i

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Solution for 2+5(i-3)=7i-15-4i equation: 



2+5(i-3)=7i-15-4i

We move all terms to the left:

2+5(i-3)-(7i-15-4i)=0

We add all the numbers together, and all the variables

5(i-3)-(3i-15)+2=0

We multiply parentheses

5i-(3i-15)-15+2=0

We get rid of parentheses

5i-3i+15-15+2=0

We add all the numbers together, and all the variables

2i+2=0

We move all terms containing i to the left, all other terms to the right

2i=-2

i=-2/2

i=-1

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