2+5(t+2)=-3(t-4)

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Solution for 2+5(t+2)=-3(t-4) equation: 



2+5(t+2)=-3(t-4)

We move all terms to the left:

2+5(t+2)-(-3(t-4))=0

We multiply parentheses

5t-(-3(t-4))+10+2=0



We calculate terms in parentheses: -(-3(t-4)), so:

-3(t-4)

We multiply parentheses

-3t+12

Back to the equation:

-(-3t+12)



We add all the numbers together, and all the variables

5t-(-3t+12)+12=0

We get rid of parentheses

5t+3t-12+12=0

We add all the numbers together, and all the variables

8t=0

t=0/8

t=0

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