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2+5x=5-12(x+2)
We move all terms to the left:
2+5x-(5-12(x+2))=0
We calculate terms in parentheses: -(5-12(x+2)), so:We get rid of parentheses
5-12(x+2)
determiningTheFunctionDomain -12(x+2)+5
We multiply parentheses
-12x-24+5
We add all the numbers together, and all the variables
-12x-19
Back to the equation:
-(-12x-19)
5x+12x+19+2=0
We add all the numbers together, and all the variables
17x+21=0
We move all terms containing x to the left, all other terms to the right
17x=-21
x=-21/17
x=-1+4/17
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