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2+8x=50+x2-6x
We move all terms to the left:
2+8x-(50+x2-6x)=0
We add all the numbers together, and all the variables
-(+x^2-6x+50)+8x+2=0
We get rid of parentheses
-x^2+6x+8x-50+2=0
We add all the numbers together, and all the variables
-1x^2+14x-48=0
a = -1; b = 14; c = -48;
Δ = b2-4ac
Δ = 142-4·(-1)·(-48)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2}{2*-1}=\frac{-16}{-2} =+8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2}{2*-1}=\frac{-12}{-2} =+6 $
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