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2+9x+1=3(3x+1)
We move all terms to the left:
2+9x+1-(3(3x+1))=0
We add all the numbers together, and all the variables
9x-(3(3x+1))+3=0
We calculate terms in parentheses: -(3(3x+1)), so:We get rid of parentheses
3(3x+1)
We multiply parentheses
9x+3
Back to the equation:
-(9x+3)
9x-9x-3+3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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