2+d=15-7/8d

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Solution for 2+d=15-7/8d equation:



2+d=15-7/8d
We move all terms to the left:
2+d-(15-7/8d)=0
Domain of the equation: 8d)!=0
d!=0/1
d!=0
d∈R
We add all the numbers together, and all the variables
d-(-7/8d+15)+2=0
We get rid of parentheses
d+7/8d-15+2=0
We multiply all the terms by the denominator
d*8d-15*8d+2*8d+7=0
Wy multiply elements
8d^2-120d+16d+7=0
We add all the numbers together, and all the variables
8d^2-104d+7=0
a = 8; b = -104; c = +7;
Δ = b2-4ac
Δ = -1042-4·8·7
Δ = 10592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{10592}=\sqrt{16*662}=\sqrt{16}*\sqrt{662}=4\sqrt{662}$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-4\sqrt{662}}{2*8}=\frac{104-4\sqrt{662}}{16} $
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+4\sqrt{662}}{2*8}=\frac{104+4\sqrt{662}}{16} $

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