2+n=(7/8)n-15

Solution for 2+n=(7/8)n-15 equation:

2+n=(7/8)n-15

We move all terms to the left:

2+n-((7/8)n-15)=0


Domain of the equation: 8)n-15)!=0

n!=0/1

n!=0

n∈R


We add all the numbers together, and all the variables

n-((+7/8)n-15)+2=0

We multiply all the terms by the denominator


n*8)n-15)-((+2*8)n-15)+7=0

We add all the numbers together, and all the variables

n*8)n-15)-(16n-15)+7=0

Wy multiply elements

8n^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{16}=0$