2+x(3x+8-1)=18

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Solution for 2+x(3x+8-1)=18 equation:



2+x(3x+8-1)=18
We move all terms to the left:
2+x(3x+8-1)-(18)=0
We add all the numbers together, and all the variables
x(3x+7)+2-18=0
We add all the numbers together, and all the variables
x(3x+7)-16=0
We multiply parentheses
3x^2+7x-16=0
a = 3; b = 7; c = -16;
Δ = b2-4ac
Δ = 72-4·3·(-16)
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{241}}{2*3}=\frac{-7-\sqrt{241}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{241}}{2*3}=\frac{-7+\sqrt{241}}{6} $

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