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2+x+2x+4=3(x+2)
We move all terms to the left:
2+x+2x+4-(3(x+2))=0
We add all the numbers together, and all the variables
3x-(3(x+2))+6=0
We calculate terms in parentheses: -(3(x+2)), so:We get rid of parentheses
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
3x-3x-6+6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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