2+x=(7/7x)-15

Solution for 2+x=(7/7x)-15 equation:

2+x=(7/7x)-15

We move all terms to the left:

2+x-((7/7x)-15)=0


Domain of the equation: 7x)-15)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x-((+7/7x)-15)+2=0

We multiply all the terms by the denominator


x*7x)-15)-((+2*7x)-15)+7=0

Wy multiply elements

7x^2+14x=0

a = 7; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·7·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*7}=\frac{-28}{14}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*7}=\frac{0}{14}
=0
$