2+x=7(x+3)-3(2-x)

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Solution for 2+x=7(x+3)-3(2-x) equation: 



2+x=7(x+3)-3(2-x)

We move all terms to the left:

2+x-(7(x+3)-3(2-x))=0

We add all the numbers together, and all the variables

x-(7(x+3)-3(-1x+2))+2=0



We calculate terms in parentheses: -(7(x+3)-3(-1x+2)), so:

7(x+3)-3(-1x+2)

We multiply parentheses

7x+3x+21-6

We add all the numbers together, and all the variables

10x+15

Back to the equation:

-(10x+15)



We get rid of parentheses

x-10x-15+2=0

We add all the numbers together, and all the variables

-9x-13=0

We move all terms containing x to the left, all other terms to the right

-9x=13

x=13/-9

x=-1+4/9

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