2,5*(2-3x)+6,3x=3*(1,2-0,6x)+1,1

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Solution for 2,5*(2-3x)+6,3x=3*(1,2-0,6x)+1,1 equation: 



2.5(2-3x)+6.3x=3(1.2-0.6x)+1.1

We move all terms to the left:

2.5(2-3x)+6.3x-(3(1.2-0.6x)+1.1)=0

We add all the numbers together, and all the variables

2.5(-3x+2)+6.3x-(3(-0.6x+1.2)+1.1)=0

We add all the numbers together, and all the variables

6.3x+2.5(-3x+2)-(3(-0.6x+1.2)+1.1)=0

We multiply parentheses

6.3x-7.5x-(3(-0.6x+1.2)+1.1)+5=0



We calculate terms in parentheses: -(3(-0.6x+1.2)+1.1), so:

3(-0.6x+1.2)+1.1

We multiply parentheses

0x+3.6+1.1

We add all the numbers together, and all the variables

x+4.7

Back to the equation:

-(x+4.7)



We add all the numbers together, and all the variables

-1.2x-(x+4.7)+5=0

We get rid of parentheses

-1.2x-x-4.7+5=0

We add all the numbers together, and all the variables

-2.2x+0.3=0

We move all terms containing x to the left, all other terms to the right

-2.2x=-0.3

x=-0.3/-2.2

x=0.3/2.2

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