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2.5x^2+8.375=59
We move all terms to the left:
2.5x^2+8.375-(59)=0
We add all the numbers together, and all the variables
2.5x^2-50.625=0
a = 2.5; b = 0; c = -50.625;
Δ = b2-4ac
Δ = 02-4·2.5·(-50.625)
Δ = 506.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{506.25}}{2*2.5}=\frac{0-\sqrt{506.25}}{5} =-\frac{\sqrt{}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{506.25}}{2*2.5}=\frac{0+\sqrt{506.25}}{5} =\frac{\sqrt{}}{5} $
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