2-(0.45x2)+0.5=

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Solution for 2-(0.45x2)+0.5= equation: 



2-(0.45x^2)+0.5=

We move all terms to the left:

2-(0.45x^2)+0.5-()=0

We add all the numbers together, and all the variables

-(0.45x^2)=0

We get rid of parentheses

-0.45x^2=0

a = -0.45; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-0.45)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-0.9}=0$

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