2-(10b-3)=1/2(20-30b

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Solution for 2-(10b-3)=1/2(20-30b equation: 



2-(10b-3)=1/2(20-30b

We move all terms to the left:

2-(10b-3)-(1/2(20-30b)=0



Domain of the equation: 2(20-30b)+2!=0

We move all terms containing b to the left, all other terms to the right

2(20-30b)!=-2

b∈R



We add all the numbers together, and all the variables

-(10b-3)-(1/2(-30b+20)+2=0

We get rid of parentheses

-10b-(1/2(-30b+20)+2+3=0

We multiply all the terms by the denominator


-10b*2(-30b+20)+2+3-(1=0

We add all the numbers together, and all the variables

-10b*2(-30b+20)=0

Wy multiply elements

-20b^2(-=0

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