2-(10b-3)=2(20-30b)

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Solution for 2-(10b-3)=2(20-30b) equation: 



2-(10b-3)=2(20-30b)

We move all terms to the left:

2-(10b-3)-(2(20-30b))=0

We add all the numbers together, and all the variables

-(10b-3)-(2(-30b+20))+2=0

We get rid of parentheses

-10b-(2(-30b+20))+3+2=0



We calculate terms in parentheses: -(2(-30b+20)), so:

2(-30b+20)

We multiply parentheses

-60b+40

Back to the equation:

-(-60b+40)



We add all the numbers together, and all the variables

-10b-(-60b+40)+5=0

We get rid of parentheses

-10b+60b-40+5=0

We add all the numbers together, and all the variables

50b-35=0

We move all terms containing b to the left, all other terms to the right

50b=35

b=35/50

b=7/10

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