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2-(2-(1+4x)-5)=10-x
We move all terms to the left:
2-(2-(1+4x)-5)-(10-x)=0
We add all the numbers together, and all the variables
-(2-(4x+1)-5)-(-1x+10)+2=0
We get rid of parentheses
-(2-(4x+1)-5)+1x-10+2=0
We calculate terms in parentheses: -(2-(4x+1)-5), so:We add all the numbers together, and all the variables
2-(4x+1)-5
determiningTheFunctionDomain -(4x+1)+2-5
We add all the numbers together, and all the variables
-(4x+1)-3
We get rid of parentheses
-4x-1-3
We add all the numbers together, and all the variables
-4x-4
Back to the equation:
-(-4x-4)
x-(-4x-4)-8=0
We get rid of parentheses
x+4x+4-8=0
We add all the numbers together, and all the variables
5x-4=0
We move all terms containing x to the left, all other terms to the right
5x=4
x=4/5
x=4/5
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