2-(2m+(2m-(2-2m)))=2

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Solution for 2-(2m+(2m-(2-2m)))=2 equation: 



2-(2m+(2m-(2-2m)))=2

We move all terms to the left:

2-(2m+(2m-(2-2m)))-(2)=0

We add all the numbers together, and all the variables

-(2m+(2m-(-2m+2)))+2-2=0

We add all the numbers together, and all the variables

-(2m+(2m-(-2m+2)))=0



We calculate terms in parentheses: -(2m+(2m-(-2m+2))), so:

2m+(2m-(-2m+2))



We calculate terms in parentheses: +(2m-(-2m+2)), so:

2m-(-2m+2)

We get rid of parentheses

2m+2m-2

We add all the numbers together, and all the variables

4m-2

Back to the equation:

+(4m-2)



We get rid of parentheses

2m+4m-2

We add all the numbers together, and all the variables

6m-2

Back to the equation:

-(6m-2)



We get rid of parentheses

-6m+2=0

We move all terms containing m to the left, all other terms to the right

-6m=-2

m=-2/-6

m=1/3

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