2-(2m+(2m-(2-m)))=2

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Solution for 2-(2m+(2m-(2-m)))=2 equation: 



2-(2m+(2m-(2-m)))=2

We move all terms to the left:

2-(2m+(2m-(2-m)))-(2)=0

We add all the numbers together, and all the variables

-(2m+(2m-(-1m+2)))+2-2=0

We add all the numbers together, and all the variables

-(2m+(2m-(-1m+2)))=0



We calculate terms in parentheses: -(2m+(2m-(-1m+2))), so:

2m+(2m-(-1m+2))



We calculate terms in parentheses: +(2m-(-1m+2)), so:

2m-(-1m+2)

We get rid of parentheses

2m+1m-2

We add all the numbers together, and all the variables

3m-2

Back to the equation:

+(3m-2)



We get rid of parentheses

2m+3m-2

We add all the numbers together, and all the variables

5m-2

Back to the equation:

-(5m-2)



We get rid of parentheses

-5m+2=0

We move all terms containing m to the left, all other terms to the right

-5m=-2

m=-2/-5

m=2/5

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