2-(3-2(X+1))=3X+2(x+2x))

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Solution for 2-(3-2(X+1))=3X+2(x+2x)) equation: 



2-(3-2(X+1))=3X+2(X+2X))

We move all terms to the left:

2-(3-2(X+1))-(3X+2(X+2X)))=0

We add all the numbers together, and all the variables

-(3-2(X+1))-(3X+2(+3X)))+2=0



We calculate terms in parentheses: -(3-2(X+1)), so:

3-2(X+1)

determiningTheFunctionDomain
-2(X+1)+3

We multiply parentheses

-2X-2+3

We add all the numbers together, and all the variables

-2X+1

Back to the equation:

-(-2X+1)



We get rid of parentheses

2X-(3X+2(+3X)))+2-1=0

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