2-(3-2(x+1))=3x+2(x-(3+2))

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Solution for 2-(3-2(x+1))=3x+2(x-(3+2)) equation: 



2-(3-2(x+1))=3x+2(x-(3+2))

We move all terms to the left:

2-(3-2(x+1))-(3x+2(x-(3+2)))=0

We add all the numbers together, and all the variables

-(3-2(x+1))-(3x+2(x-5))+2=0



We calculate terms in parentheses: -(3-2(x+1)), so:

3-2(x+1)

determiningTheFunctionDomain
-2(x+1)+3

We multiply parentheses

-2x-2+3

We add all the numbers together, and all the variables

-2x+1

Back to the equation:

-(-2x+1)





We calculate terms in parentheses: -(3x+2(x-5)), so:

3x+2(x-5)

We multiply parentheses

3x+2x-10

We add all the numbers together, and all the variables

5x-10

Back to the equation:

-(5x-10)



We get rid of parentheses

2x-5x-1+10+2=0

We add all the numbers together, and all the variables

-3x+11=0

We move all terms containing x to the left, all other terms to the right

-3x=-11

x=-11/-3

x=3+2/3

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