2-(3-2(x+1))=3x+2(x-(3+2x)

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Solution for 2-(3-2(x+1))=3x+2(x-(3+2x) equation: 



2-(3-2(x+1))=3x+2(x-(3+2x)

We move all terms to the left:

2-(3-2(x+1))-(3x+2(x-(3+2x))=0

We add all the numbers together, and all the variables

-(3-2(x+1))-(3x+2(x-(2x+3))+2=0



We calculate terms in parentheses: -(3-2(x+1)), so:

3-2(x+1)

determiningTheFunctionDomain
-2(x+1)+3

We multiply parentheses

-2x-2+3

We add all the numbers together, and all the variables

-2x+1

Back to the equation:

-(-2x+1)



We get rid of parentheses

2x-(3x+2(x-(2x+3))+2-1=0

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