2-(3-2(x+1))=3x+2(x-3+2x))

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Solution for 2-(3-2(x+1))=3x+2(x-3+2x)) equation: 



2-(3-2(x+1))=3x+2(x-3+2x))

We move all terms to the left:

2-(3-2(x+1))-(3x+2(x-3+2x)))=0

We add all the numbers together, and all the variables

-(3-2(x+1))-(3x+2(3x-3)))+2=0



We calculate terms in parentheses: -(3-2(x+1)), so:

3-2(x+1)

determiningTheFunctionDomain
-2(x+1)+3

We multiply parentheses

-2x-2+3

We add all the numbers together, and all the variables

-2x+1

Back to the equation:

-(-2x+1)



We get rid of parentheses

2x-(3x+2(3x-3)))+2-1=0

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