2-(3-2(x+1)=3x+2(3+2x))

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Solution for 2-(3-2(x+1)=3x+2(3+2x)) equation:



2-(3-2(x+1)=3x+2(3+2x))
We move all terms to the left:
2-(3-2(x+1)-(3x+2(3+2x)))=0
We add all the numbers together, and all the variables
-(3-2(x+1)-(3x+2(2x+3)))+2=0
We calculate terms in parentheses: -(3-2(x+1)-(3x+2(2x+3))), so:
3-2(x+1)-(3x+2(2x+3))
determiningTheFunctionDomain -2(x+1)-(3x+2(2x+3))+3
We multiply parentheses
-2x-(3x+2(2x+3))-2+3
We calculate terms in parentheses: -(3x+2(2x+3)), so:
3x+2(2x+3)
We multiply parentheses
3x+4x+6
We add all the numbers together, and all the variables
7x+6
Back to the equation:
-(7x+6)
We add all the numbers together, and all the variables
-2x-(7x+6)+1
We get rid of parentheses
-2x-7x-6+1
We add all the numbers together, and all the variables
-9x-5
Back to the equation:
-(-9x-5)
We get rid of parentheses
9x+5+2=0
We add all the numbers together, and all the variables
9x+7=0
We move all terms containing x to the left, all other terms to the right
9x=-7
x=-7/9
x=-7/9

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