2-(3/4)=(5/6)r+5

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Solution for 2-(3/4)=(5/6)r+5 equation: 



2-(3/4)=(5/6)r+5

We move all terms to the left:

2-(3/4)-((5/6)r+5)=0



Domain of the equation: 6)r+5)!=0

r!=0/1

r!=0

r∈R



We add all the numbers together, and all the variables

-((+5/6)r+5)+2-(+3/4)=0

We get rid of parentheses

-((+5/6)r+5)+2-3/4=0

We calculate fractions


()/6r+5)*4)+(-18r)/6r+5)*4)+2=0

We calculate fractions


(()*6r)/36r^2-18r)*6r)/36r^2+5*4)+(=0

We calculate fractions

We do not support erpression: r^4

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