2-(32-4x)=4(22+7x)

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Solution for 2-(32-4x)=4(22+7x) equation: 



2-(32-4x)=4(22+7x)

We move all terms to the left:

2-(32-4x)-(4(22+7x))=0

We add all the numbers together, and all the variables

-(-4x+32)-(4(7x+22))+2=0

We get rid of parentheses

4x-(4(7x+22))-32+2=0



We calculate terms in parentheses: -(4(7x+22)), so:

4(7x+22)

We multiply parentheses

28x+88

Back to the equation:

-(28x+88)



We add all the numbers together, and all the variables

4x-(28x+88)-30=0

We get rid of parentheses

4x-28x-88-30=0

We add all the numbers together, and all the variables

-24x-118=0

We move all terms containing x to the left, all other terms to the right

-24x=118

x=118/-24

x=-4+11/12

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