2-(3x-5)=42x+3-x

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Solution for 2-(3x-5)=42x+3-x equation: 



2-(3x-5)=42x+3-x

We move all terms to the left:

2-(3x-5)-(42x+3-x)=0

We add all the numbers together, and all the variables

-(3x-5)-(41x+3)+2=0

We get rid of parentheses

-3x-41x+5-3+2=0

We add all the numbers together, and all the variables

-44x+4=0

We move all terms containing x to the left, all other terms to the right

-44x=-4

x=-4/-44

x=1/11

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