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2-(4x+6)=5(2/3+x)
We move all terms to the left:
2-(4x+6)-(5(2/3+x))=0
Domain of the equation: 3+x))!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x))!=-3
x!=-3/1
x!=-3
x∈R
-(4x+6)-(5(+x+2/3))+2=0
We get rid of parentheses
-4x-(5(+x+2/3))-6+2=0
We multiply all the terms by the denominator
-4x*3))-(5(+x+2-6*3))+2*3))=0
We add all the numbers together, and all the variables
-4x*3))-(5(x-16))+2*3))=0
We add all the numbers together, and all the variables
-4x*3))-(5(x=0
Wy multiply elements
-12x^2=0
a = -12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-12)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-24}=0$
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