2-(4x-19)=5(x-2)

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Solution for 2-(4x-19)=5(x-2) equation: 



2-(4x-19)=5(x-2)

We move all terms to the left:

2-(4x-19)-(5(x-2))=0

We get rid of parentheses

-4x-(5(x-2))+19+2=0



We calculate terms in parentheses: -(5(x-2)), so:

5(x-2)

We multiply parentheses

5x-10

Back to the equation:

-(5x-10)



We add all the numbers together, and all the variables

-4x-(5x-10)+21=0

We get rid of parentheses

-4x-5x+10+21=0

We add all the numbers together, and all the variables

-9x+31=0

We move all terms containing x to the left, all other terms to the right

-9x=-31

x=-31/-9

x=3+4/9

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