2-(b/3)=-(5/2)

Solution for 2-(b/3)=-(5/2) equation:

2-(b/3)=-(5/2)

We move all terms to the left:

2-(b/3)-(-(5/2))=0

We add all the numbers together, and all the variables

-(+b/3)+2-(-(+5/2))=0

We get rid of parentheses

-b/3+2-(-(+5/2))=0

We calculate fractions


(-2b^2)/()+2+()/()=0

We add all the numbers together, and all the variables

(-2b^2)/()+3=0

We multiply all the terms by the denominator


(-2b^2)+3*()=0

We add all the numbers together, and all the variables

(-2b^2)=0

We get rid of parentheses

-2b^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{-4}=0$