2-(r-4)+7r=11

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Solution for 2-(r-4)+7r=11 equation: 



2-(r-4)+7r=11

We move all terms to the left:

2-(r-4)+7r-(11)=0

We add all the numbers together, and all the variables

7r-(r-4)-9=0

We get rid of parentheses

7r-r+4-9=0

We add all the numbers together, and all the variables

6r-5=0

We move all terms containing r to the left, all other terms to the right

6r=5

r=5/6

r=5/6

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