2-(x+4)-6(2x-2)=18-4x

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Solution for 2-(x+4)-6(2x-2)=18-4x equation: 



2-(x+4)-6(2x-2)=18-4x

We move all terms to the left:

2-(x+4)-6(2x-2)-(18-4x)=0

We add all the numbers together, and all the variables

-(x+4)-6(2x-2)-(-4x+18)+2=0

We multiply parentheses

-(x+4)-12x-(-4x+18)+12+2=0

We get rid of parentheses

-x-12x+4x-4-18+12+2=0

We add all the numbers together, and all the variables

-9x-8=0

We move all terms containing x to the left, all other terms to the right

-9x=8

x=8/-9

x=-8/9

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