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2-(x+5)-(x-2)=-3(x-3)
We move all terms to the left:
2-(x+5)-(x-2)-(-3(x-3))=0
We get rid of parentheses
-x-x-(-3(x-3))-5+2+2=0
We calculate terms in parentheses: -(-3(x-3)), so:We add all the numbers together, and all the variables
-3(x-3)
We multiply parentheses
-3x+9
Back to the equation:
-(-3x+9)
-2x-(-3x+9)-1=0
We get rid of parentheses
-2x+3x-9-1=0
We add all the numbers together, and all the variables
x-10=0
We move all terms containing x to the left, all other terms to the right
x=10
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