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2-(x+5)=2(x+1)-6x
We move all terms to the left:
2-(x+5)-(2(x+1)-6x)=0
We get rid of parentheses
-x-(2(x+1)-6x)-5+2=0
We calculate terms in parentheses: -(2(x+1)-6x), so:We add all the numbers together, and all the variables
2(x+1)-6x
We add all the numbers together, and all the variables
-6x+2(x+1)
We multiply parentheses
-6x+2x+2
We add all the numbers together, and all the variables
-4x+2
Back to the equation:
-(-4x+2)
-1x-(-4x+2)-3=0
We get rid of parentheses
-1x+4x-2-3=0
We add all the numbers together, and all the variables
3x-5=0
We move all terms containing x to the left, all other terms to the right
3x=5
x=5/3
x=1+2/3
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