2-(x-5)+3=-10+3x+20

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Solution for 2-(x-5)+3=-10+3x+20 equation: 



2-(x-5)+3=-10+3x+20

We move all terms to the left:

2-(x-5)+3-(-10+3x+20)=0

We add all the numbers together, and all the variables

-(x-5)-(3x+10)+2+3=0

We add all the numbers together, and all the variables

-(x-5)-(3x+10)+5=0

We get rid of parentheses

-x-3x+5-10+5=0

We add all the numbers together, and all the variables

-4x=0

x=0/-4

x=0

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