2-(x-5)=10(x+3)

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Solution for 2-(x-5)=10(x+3) equation:



2-(x-5)=10(x+3)
We move all terms to the left:
2-(x-5)-(10(x+3))=0
We get rid of parentheses
-x-(10(x+3))+5+2=0
We calculate terms in parentheses: -(10(x+3)), so:
10(x+3)
We multiply parentheses
10x+30
Back to the equation:
-(10x+30)
We add all the numbers together, and all the variables
-1x-(10x+30)+7=0
We get rid of parentheses
-1x-10x-30+7=0
We add all the numbers together, and all the variables
-11x-23=0
We move all terms containing x to the left, all other terms to the right
-11x=23
x=23/-11
x=-2+1/11

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