2-(y+1)(y+1)=5-3(y-5y-9)-y2

Solution for 2-(y+1)(y+1)=5-3(y-5y-9)-y2 equation:

2-(y+1)(y+1)=5-3(y-5y-9)-y2

We move all terms to the left:

2-(y+1)(y+1)-(5-3(y-5y-9)-y2)=0

We add all the numbers together, and all the variables

-(y+1)(y+1)-(5-3(-4y-9)-y2)+2=0

We multiply parentheses ..

-(+y^2+y+y+1)-(5-3(-4y-9)-y2)+2=0


We calculate terms in parentheses: -(5-3(-4y-9)-y2), so:

5-3(-4y-9)-y2

determiningTheFunctionDomain
-3(-4y-9)-y2+5

We add all the numbers together, and all the variables

-1y^2-3(-4y-9)+5

We multiply parentheses

-1y^2+12y+27+5

We add all the numbers together, and all the variables

-1y^2+12y+32

Back to the equation:

-(-1y^2+12y+32)


We get rid of parentheses

-y^2+1y^2-y-y-12y-1-32+2=0

We add all the numbers together, and all the variables

-14y-31=0

We move all terms containing y to the left, all other terms to the right

-14y=31

y=31/-14

y=-2+3/14