2-(y-3)-(y+3)=20-4(y+3)

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Solution for 2-(y-3)-(y+3)=20-4(y+3) equation: 



2-(y-3)-(y+3)=20-4(y+3)

We move all terms to the left:

2-(y-3)-(y+3)-(20-4(y+3))=0

We get rid of parentheses

-y-y-(20-4(y+3))+3-3+2=0



We calculate terms in parentheses: -(20-4(y+3)), so:

20-4(y+3)

determiningTheFunctionDomain
-4(y+3)+20

We multiply parentheses

-4y-12+20

We add all the numbers together, and all the variables

-4y+8

Back to the equation:

-(-4y+8)



We add all the numbers together, and all the variables

-2y-(-4y+8)+2=0

We get rid of parentheses

-2y+4y-8+2=0

We add all the numbers together, and all the variables

2y-6=0

We move all terms containing y to the left, all other terms to the right

2y=6

y=6/2

y=3

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