2-(z+3)-z=-z-4(z+2)

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Solution for 2-(z+3)-z=-z-4(z+2) equation: 



2-(z+3)-z=-z-4(z+2)

We move all terms to the left:

2-(z+3)-z-(-z-4(z+2))=0

We add all the numbers together, and all the variables

-1z-(z+3)-(-z-4(z+2))+2=0

We get rid of parentheses

-1z-z-(-z-4(z+2))-3+2=0



We calculate terms in parentheses: -(-z-4(z+2)), so:

-z-4(z+2)

We add all the numbers together, and all the variables

-1z-4(z+2)

We multiply parentheses

-1z-4z-8

We add all the numbers together, and all the variables

-5z-8

Back to the equation:

-(-5z-8)



We add all the numbers together, and all the variables

-2z-(-5z-8)-1=0

We get rid of parentheses

-2z+5z+8-1=0

We add all the numbers together, and all the variables

3z+7=0

We move all terms containing z to the left, all other terms to the right

3z=-7

z=-7/3

z=-2+1/3

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