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2-1/4x=3/8x+3
We move all terms to the left:
2-1/4x-(3/8x+3)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 8x+3)!=0We get rid of parentheses
x∈R
-1/4x-3/8x-3+2=0
We calculate fractions
(-8x)/32x^2+(-12x)/32x^2-3+2=0
We add all the numbers together, and all the variables
(-8x)/32x^2+(-12x)/32x^2-1=0
We multiply all the terms by the denominator
(-8x)+(-12x)-1*32x^2=0
Wy multiply elements
-32x^2+(-8x)+(-12x)=0
We get rid of parentheses
-32x^2-8x-12x=0
We add all the numbers together, and all the variables
-32x^2-20x=0
a = -32; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·(-32)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*-32}=\frac{0}{-64} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*-32}=\frac{40}{-64} =-5/8 $
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