2-1/5(4x+1)=1/3(2x+1)

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Solution for 2-1/5(4x+1)=1/3(2x+1) equation: 



2-1/5(4x+1)=1/3(2x+1)

We move all terms to the left:

2-1/5(4x+1)-(1/3(2x+1))=0



Domain of the equation: 5(4x+1)!=0

x∈R





Domain of the equation: 3(2x+1))!=0

x∈R



We calculate fractions


(-3x2/(5(4x+1)*3(2x+1)))+(-5x4/(5(4x+1)*3(2x+1)))+2=0



We calculate terms in parentheses: +(-3x2/(5(4x+1)*3(2x+1))), so:

-3x2/(5(4x+1)*3(2x+1))

We multiply all the terms by the denominator


-3x2

We add all the numbers together, and all the variables

-3x^2

Back to the equation:

+(-3x^2)





We calculate terms in parentheses: +(-5x4/(5(4x+1)*3(2x+1))), so:

-5x4/(5(4x+1)*3(2x+1))

We multiply all the terms by the denominator


-5x4

We add all the numbers together, and all the variables

-5x^4

We do not support expression: x^4

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