2-2(1+8x)=8x+7(-4-4x)

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Solution for 2-2(1+8x)=8x+7(-4-4x) equation: 



2-2(1+8x)=8x+7(-4-4x)

We move all terms to the left:

2-2(1+8x)-(8x+7(-4-4x))=0

We add all the numbers together, and all the variables

-2(8x+1)-(8x+7(-4x-4))+2=0

We multiply parentheses

-16x-(8x+7(-4x-4))-2+2=0



We calculate terms in parentheses: -(8x+7(-4x-4)), so:

8x+7(-4x-4)

We multiply parentheses

8x-28x-28

We add all the numbers together, and all the variables

-20x-28

Back to the equation:

-(-20x-28)



We add all the numbers together, and all the variables

-16x-(-20x-28)=0

We get rid of parentheses

-16x+20x+28=0

We add all the numbers together, and all the variables

4x+28=0

We move all terms containing x to the left, all other terms to the right

4x=-28

x=-28/4

x=-7

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