2-2(3x-10)+8x=7x+20+7x

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Solution for 2-2(3x-10)+8x=7x+20+7x equation:



2-2(3x-10)+8x=7x+20+7x
We move all terms to the left:
2-2(3x-10)+8x-(7x+20+7x)=0
We add all the numbers together, and all the variables
-2(3x-10)+8x-(14x+20)+2=0
We add all the numbers together, and all the variables
8x-2(3x-10)-(14x+20)+2=0
We multiply parentheses
8x-6x-(14x+20)+20+2=0
We get rid of parentheses
8x-6x-14x-20+20+2=0
We add all the numbers together, and all the variables
-12x+2=0
We move all terms containing x to the left, all other terms to the right
-12x=-2
x=-2/-12
x=1/6

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