2-2(7+5r)=-6(r-8)

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Solution for 2-2(7+5r)=-6(r-8) equation: 



2-2(7+5r)=-6(r-8)

We move all terms to the left:

2-2(7+5r)-(-6(r-8))=0

We add all the numbers together, and all the variables

-2(5r+7)-(-6(r-8))+2=0

We multiply parentheses

-10r-(-6(r-8))-14+2=0



We calculate terms in parentheses: -(-6(r-8)), so:

-6(r-8)

We multiply parentheses

-6r+48

Back to the equation:

-(-6r+48)



We add all the numbers together, and all the variables

-10r-(-6r+48)-12=0

We get rid of parentheses

-10r+6r-48-12=0

We add all the numbers together, and all the variables

-4r-60=0

We move all terms containing r to the left, all other terms to the right

-4r=60

r=60/-4

r=-15

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